In  a  AaBBCcDd x AaBBCcDd cross, the heterozygous gene pairs (n) is 3
   (note:  B  is not heterozygous). Assuming independent assortment, each
   parent  can  produce  8  (2^3)  different  gametes  and yield 27 (3^3)
   different genotypes and 8 (2^3) different phenotypes in the F[2].